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Disguised Quadratic

The trick to these problems and any “disguised quadratic” is to recognize that it is a
disguised quadratic. Notice that in every problem of this type, there is a relationship
between the leading term and the middle term! The power of the leading term is double
that of the middle term.

Once you have recognized that the problem is a disguised quadratic, you should make the
substitution u = middle ex pression .

Here are some examples:

Once you have made the correct substitution, you should have a quadratic equation . Now
you can try to factor or use the quadratic formula .

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