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Areas and Volume

The area between the curves y = f(x) and y = g(x) and between x = a and x = b is

An analogous formula holds for the area between the curves y = c and y = d and x = f(y) and x = g(y):

For a solid S lying between x = a and x = b with cross-sectional area function A(x) (A continuous),
the volume of S is

Again, an analogous formula holds for the volume of a solid S lying between y = c and y = d with
cross-sectional area function A(y) (A continuous). In this case,

1.

 

2.

 

3. (6.1.50) Find the number a such that the line x = a bisects the area under the curve y = 1/(x^2)
for 1≤x≤4. Also, find the number b such that the line y = b bisects the same area.

Solution : We want our line x = a to split our areas. That is, we want an a so that
Taking the integrals, we find Solving for a , we find that

For the second part, we want to split the areas using a horizontal line y = b. A horizontal line
will give us a wedge above the line and a region below that includes a rectangle sitting below the
line y = 1/16. The area of the lower region is The first term comes
from the rectangle of length 3 between 1 and 4 and height 1/16. The second terms comes from
determining the area between the curve and x = 1. The upper region has area given by
dy. We set these two equal to each other and integrate to get

We simplify this to get To solve for b , we set c^2 = b and consider
We solve for c using the quadratic formula to get Thus
Squaring this we get

Solution: The solid looks like the space between a funnel and a cylinder. We split this solid
into two different regions : the lower one consists of a cylinder with a hole and the upper region
is a triangle rotated around the line x = 1. The lower region has cross-sectional area
and the upper region has cross-sectional area
Then we find

5. Suppose 2≤f(x)≤4 for all x. Which of the following is false:

(B) The antiderivative of f is always positive .

(D) The antiderivative of f is always negative .

Solution: (A) is true since f(x)≥2 for all x. (C) is true since 2≤f(x)≤4 implies that
(E) is true since For (B) and (D), note
that an antiderivative of f isby the Fundamental Theorem of Calculus. Since
f(x) > 0, g(x) > 0 for any x. Thus (B) is true while (D) is false. Hence the answer is (E).

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