Your Algebra Homework Can Now Be Easier Than Ever!

Maxima and Minima for Multivariable Functions

Recall how we determine maxima and minima for single- variable functions : for some function
f(x), we look for critical points (i.e. points for which f'(x) = 0) and at such a point, we consider
f''(x):

We now want to extend this work to multivariable functions.

Iterated Partial Derivatives
Now the first task is to generalize the notion of higher- order derivatives from single-variable
calculus. To do this, we naturally want to differentiate the partial derivatives of our function. For
example, consider f : R2 → R1 which is C1 (i.e. its partial derivatives exist and are continuous).
We can consider each partial of f and differentiate it to get

We call such derivatives iterated partial derivatives, while and are called
mixed partial derivatives. An important fact is that if f : Rn → Rm is C2, then the mixed
partial derivatives of f are equal. That is

This is an important result, and we will be using it often. You should definitely commit it (and its
conditions) to memory.

Exercise: Compute all second-order partial derivatives for (do not assume the
mixed partials are equal).

Taylor’s Theorem
Let us remind ourselves of the statement of Taylor’s theorem from single-variable calculus:

We will not delve into the proof of Taylor’s theorem for the single-variable or the multivariable
case. But let us state the theorem in the general case:

For the sake of exposition, let us state what happens when we take first and second-order derivatives:

In the case of single-variable functions, we can expand our function f(x) in an infinite power
series, which we call the Taylor series:

provided you can show that → 0 as k → 0. We can do the same for multivariable
functions by replacing the preceding terms by the corresponding ones involving partial derivatives
provided we can show → 0 as k → 0.

Exercise: Compute the second-order Taylor expansion for f(x, y) = (x + y)2 at (0, 0).

Local Extrema of Real -Valued Functions
We begin with a few basic definitions:

Definition 1.

As you may remember from single-variable calculus, every extremum is a critical point. But
remember that not every critical point is an extremum. This yields the following theorem:

Theorem 1 (First derivative test for local extrema).

From the definition of Df(), we rephrase the first derivative test as just

Now the next goal is to develop a second-derivative test for multivariable (real-valued) functions.
In general, this second-derivative test is a fairly complicated mathematical object . We introduce
some notation to help us beginning with the Hessian:

Definition 2 (The Hessian).

The Hessian is an example of a quadratic function . These are functions Ø: Rn → R such that



for some values . The reason these are called quadratic functions is reflected by the fact that



Interpreting a quadratic function in terms of matrix multiplication is useful to know:

Now if we evaluate the Hessian at a critical point of f (i.e. where Df() = 0), Taylor’s
theorem tells us

Thus we see that at a critical point, the Hessian is just the first non-constant term in the Taylor
series for f. We want to have a little more notation:

Definition 3 (Positive- and negative-definite).

Observe that if n = 1, we find , which is positive -definite if and only if
f''() > 0. This fits perfectly with the second -derivative test for single-variable functions and
motivates the following theorem.

Theorem 2 (Second derivative test for local extrema).

In fact the extrema determined by this test are strict in the sense that a local maxima (or minima)
is strict if (or ) for all nearby .
In the special case that n = 2, the Hessian for a function f(x, y) is just

We can determine easily a criterion for determining whether a quadratic function given by a 2 × 2
matrix is postive-definite ( or negative -definite):

Lemma 1.

The proof of this lemma is carried out on p. 214-5 and is rather straightforward, so do take a look
at it. We can also arrive at the following formulation :

In fact, similar criteria exist for general n × n symmetric matrices. We consider the n square
submatrices along the diagonal of B:
 

Then B is positive-definite (i.e. the quadratic function defined by B) if and only if

Moreover B is negative-definite if and only if the signs of these sub-determinants alternate between
> 0 and < 0. If all of the sub-determinants are non- zero but the matrix is neither positive- nor
negative-definite, the critical point is of saddle type.

Let us go back to the n = 2 case and restate the second-derivative test in this special case.

Theorem 3 (Second derivative max-min test for functions of two variables).

If D < 0 in this theorem, we will have a saddle point. If D = 0, we will need further analysis
(and will not worry about this situation for now). Critical points for which D ≠ 0 are called
nondegenerate critical points. The remaining critical points, i.e. where D = 0, are called
degenerate critical points and the behavior of the function at those points is determined by
other methods (e.g. level sets or sections).

Prev Next

Start solving your Algebra Problems in next 5 minutes!

Algebra Helper
Download (and optional CD)

Only $39.99

Click to Buy Now:


OR

2Checkout.com is an authorized reseller
of goods provided by Sofmath

Attention: We are currently running a special promotional offer for Algebra-Answer.com visitors -- if you order Algebra Helper by midnight of November 23rd you will pay only $39.99 instead of our regular price of $74.99 -- this is $35 in savings ! In order to take advantage of this offer, you need to order by clicking on one of the buttons on the left, not through our regular order page.

If you order now you will also receive 30 minute live session from tutor.com for a 1$!

You Will Learn Algebra Better - Guaranteed!

Just take a look how incredibly simple Algebra Helper is:

Step 1 : Enter your homework problem in an easy WYSIWYG (What you see is what you get) algebra editor:

Step 2 : Let Algebra Helper solve it:

Step 3 : Ask for an explanation for the steps you don't understand:



Algebra Helper can solve problems in all the following areas:

  • simplification of algebraic expressions (operations with polynomials (simplifying, degree, synthetic division...), exponential expressions, fractions and roots (radicals), absolute values)
  • factoring and expanding expressions
  • finding LCM and GCF
  • (simplifying, rationalizing complex denominators...)
  • solving linear, quadratic and many other equations and inequalities (including basic logarithmic and exponential equations)
  • solving a system of two and three linear equations (including Cramer's rule)
  • graphing curves (lines, parabolas, hyperbolas, circles, ellipses, equation and inequality solutions)
  • graphing general functions
  • operations with functions (composition, inverse, range, domain...)
  • simplifying logarithms
  • basic geometry and trigonometry (similarity, calculating trig functions, right triangle...)
  • arithmetic and other pre-algebra topics (ratios, proportions, measurements...)

ORDER NOW!

Algebra Helper
Download (and optional CD)

Only $39.99

Click to Buy Now:


OR

2Checkout.com is an authorized reseller
of goods provided by Sofmath
Check out our demo!
 
"It really helped me with my homework.  I was stuck on some problems and your software walked me step by step through the process..."
C. Sievert, KY
 
 
Sofmath
19179 Blanco #105-234
San Antonio, TX 78258
Phone: (512) 788-5675
Fax: (512) 519-1805
 

Home   : :   Features   : :   Demo   : :   FAQ   : :   Order

Copyright © 2004-2024, Algebra-Answer.Com.  All rights reserved.